CUET · PHYSICS · PYQ PAPER 2023
The current flowing through the two bulbs marked as 60 W, 240 V each when connected in series with 240 V source is:
- A 0.125 A
- B 0.25 A
- C 4 A
- D 2 A
Answer & Solution
Correct Answer
(A) 0.125 A
Step-by-step Solution
Detailed explanation
\( R_{total} = 2 \times \frac{V_{bulb}^2}{P_{bulb}} = 2 \times \frac{(240 \text{ V})^2}{60 \text{ W}} = 1920 \Omega \) \( I = \frac{V_{source}}{R_{total}} = \frac{240 \text{ V}}{1920 \Omega} = 0.125 \text{ A} \)
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