CUET · PHYSICS · PYQ PAPER 2025
The current and voltage in an a. c. circuit are given as
\( I = 50 \sin(50t) \text{ mA} \),
\( V = 100 \sin(50t + \pi/3) \text{ volt} \).
The power dissipated in the circuit is
- A 1.25 W
- B 2.50 W
- C 3.1250 W
- D 4.10 W
Answer & Solution
Correct Answer
(A) 1.25 W
Step-by-step Solution
Detailed explanation
\( V_0 = 100 \text{ V}, I_0 = 50 \text{ mA} = 0.05 \text{ A}, \phi = \pi/3 \) \( P = \frac{V_0 I_0}{2} \cos(\phi) \) \( P = \frac{100 \times 0.05}{2} \cos(\pi/3) \) \( P = \frac{5}{2} \times \frac{1}{2} = 1.25 \text{ W} \)
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