CUET · PHYSICS · PYQ PAPER 2025
The current and power dissipation in an inductor coil are 2 A and 200 W, respectively.
When connected to an alternating source of 220 V, 50 Hz. The resistance and inductance of the coil are (take \( \pi^2 = 10 \)):
- A \( 50 \text{ } \Omega \) and 0.511 H
- B \( 50 \text{ } \Omega \) and 0.312 H
- C \( 100 \text{ } \Omega \) and 0.511 H
- D \( 100 \text{ } \Omega \) and 0.312 H
Answer & Solution
Correct Answer
(B) \( 50 \text{ } \Omega \) and 0.312 H
Step-by-step Solution
Detailed explanation
\( R = \frac{P}{I^2} \) \( R = \frac{200}{2^2} = 50 \, \Omega \) \( Z = \frac{V}{I} \) \( Z = \frac{220}{2} = 110 \, \Omega \) \( X_L = \sqrt{Z^2 - R^2} \) \( X_L = \sqrt{110^2 - 50^2} = \sqrt{12100 - 2500} = \sqrt{9600} = 40 \sqrt{6} \, \Omega \) \( L = \frac{X_L}{2 \pi f} \)…
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