CUET · PHYSICS · PYQ PAPER 2023
The charge flowing in a conductor varies with time as \(q(t) = (8t^2 - 4t + 5)C\). Then the current changes at the rate of :
- A \(4 Ag ^{-1}\)
- B \(12 As ^{-1}\)
- C \(16 As ^{-1}\)
- D \(17 As ^{-1}\)
Answer & Solution
Correct Answer
(C) \(16 As ^{-1}\)
Step-by-step Solution
Detailed explanation
\(I = \frac{dq}{dt} = \frac{d}{dt}(8t^2 - 4t + 5) = (16t - 4)A\) \(\frac{dI}{dt} = \frac{d}{dt}(16t - 4) = 16 As^{-1}\)
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