The capacity of a parallel plate capacitor does not depend on :

A storage battery of emf 8.0 V and internal resistance 0.5 \(\Omega\) is being charged by a 60 V dc supply using a series resistor of 12.5 \(\Omega\). The terminal potential difference between the terminals of the battery during charging is

A long solenoid with 30 turns/cm has a small loop of area \( 3 \text{ cm}^2 \) placed inside it normal to its axis. If the current in the solenoid changes steadily from 3.0 A to 6.0 A in 0.1 s, the induced emf in the loop is :

The far point of a myopic person is 80 cm. The power of corrective lens will be

Daily life phenomena based on scattering of light are
(A) Blue colour of sky
(B) Clouds appearing white
(C) Twinkling of stars
(D) Danger signals being red
Choose the correct answer from the options given below:

An electron (mass \(9 \times 10^{-31} \text{ kg}\) and charge \(1.6 \times 10^{-19} \text{ C}\)) moving with a speed of \(5.0 \times 10^7 \text{ m/s}\) enters a region of uniform magnetic field of strength 0.04 T which is perpendicular to its velocity. The radius of the circular path it follows is:

Match List-I with List-II

List-I (Formula)	List-II (Physical quantity)
(A) \( neAv_d \)	(I) Mobility
(B) \(\frac{v_d}{E}\)	(II) Current
(C) \(\frac{n e^2 \tau}{m}\)	(III) Conductivity
(D) \(\frac{m}{n e^2 \tau}\)	(IV) Resistivity

Choose the correct answer from the options given below:

Let the matrix \(A=\left[\begin{array}{ll}2 & 3 \\ 1 & 4\end{array}\right]\). Then which of the following are true?
(A) \(\operatorname{adj} A =\left[\begin{array}{cc}4 & -3 \\ -1 & 2\end{array}\right]\)
(B) \(\operatorname{det}( A )=5\)
(C) \(\operatorname{det}(\operatorname{adj} A )=25\)
(D) If \(A^3=\left[\begin{array}{ll}a & b \\ c & d\end{array}\right]\), then \(a+b=c+d\)
Choose the correct answer from the options given below :

Read the passage carefully and answer the Questions
Molar conductivity \(\left( \Lambda _m\right)\) of a solution at a given concentration (c) is the conductance of volume, V of solution, containing one mole of electrolyte kept between the two electrodes with area of cross-section A and at a distance of unit length. It increases with the decrease in concentration and when the concentration approaches zero, the molar conductivity is called limiting molar conductivity \(\Lambda_m^0\). For a strong electrolyte, \(\left( \Lambda _m\right)\) increases linearly with dilution and is given by \(\Lambda_m=\Lambda_m^0-A c^{1 / 2}\).The value of the constant A for a given solvent depends on the type of electrolyte along with temperature. According to Kohlrausch law, the value of \(\Lambda_m^0\) for an electrolyte is \(\Lambda_m^0=\nu_{+} \lambda_{+}^0+\nu_{-} \lambda_{-}^0\), where \(\nu_{+}\)and \(\nu_{-}\) where v₊ and v_- are the number of cations and anions, respectively, per molecule of the electrolyte and \(\lambda_{+}^0\) and \(\lambda_{-}^0\) are limiting molar conductivities of cation and anion, respectively. Kohlrausch law
finds many applications, like determining the solubility of a sparingly soluble salt, determining the degree of dissociation \(\left(\Lambda_m / \Lambda_m^0\right)\), and the dissociation constant of a weak electrolyte.
Which one of the following has a different value of constant A in water?

Study the following figure and answer the questions:


Choose the correct statements from the following.
A. tRNA has an anticodon loop
B. tRNA look like a inverted J
C. There are no tRNAs for stop codons
D. tRNA has clover-leaf like secondary structure
Choose the correct answer from the options given below:

The menstrual flow results due to:
A. Increased estrogen levels
B. When released ovum is not fertilized
C. When pregnancy occurs
D. Breakdown of the endometrial lining of the uterus and its blood vessels

MONOHYBRID CROSS
The inheritance of flower color in the dog flower (Snapdragon or Antirrhinum sp.) can be understood by crossbreeding between true-breeding red-flowered (RR) and true-breeding white-flowered plants (rr). When they were crossed, F₁ (Rr) was pink. When F₁ was self-pollinated, the F₂ results were Red, Pink and White. Here the genotype ratios were exactly as expected, but the phenotype ratios have been changed. What happened was that R was not completely dominant over r and this made it possible to distinguish Rr as pink from RR (Red) and rr (White).
What will be the phenotypic ratio in F₂ generation when F₁ (Rr) was self-pollinated?

Sickle-cell anaemia is: