CUET · PHYSICS · PYQ PAPER 2023
The capacitance of a parallel capacitor plate, when a slab of material of dielectric constant \(k\) having same area as the plates of a parallel plate capacitor but thickness \(\frac{d}{2}\) (where 'd' is the separation of the plates) is inserted between the plates, will be :
(Given \(C _0=\) capacitance of capacitor with air as medium between plates)
- A \(C=\frac{2 k}{(k+1)} C\) 。
- B \(C=\frac{(k+1)}{2 k} C_0\)
- C \(C=2 C_{\circ}\)
- D \(C=C_0\)
Answer & Solution
Correct Answer
(A) \(C=\frac{2 k}{(k+1)} C\) 。
Step-by-step Solution
Detailed explanation
\(C_0 = \frac{\epsilon_0 A}{d}\) \(C = \frac{\epsilon_0 A}{(d-t) + \frac{t}{k}}\) \(C = \frac{\epsilon_0 A}{(d-\frac{d}{2}) + \frac{\frac{d}{2}}{k}}\) \(C = \frac{\epsilon_0 A}{\frac{d}{2} + \frac{d}{2k}}\)…
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