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CUET · PHYSICS · PYQ PAPER 2023

The capacitance of a parallel capacitor plate, when a slab of material of dielectric constant \(k\) having same area as the plates of a parallel plate capacitor but thickness \(\frac{d}{2}\) (where 'd' is the separation of the plates) is inserted between the plates, will be :
(Given \(C _0=\) capacitance of capacitor with air as medium between plates)

  1. A \(C=\frac{2 k}{(k+1)} C\) 。
  2. B \(C=\frac{(k+1)}{2 k} C_0\)
  3. C \(C=2 C_{\circ}\)
  4. D \(C=C_0\)
Verified Solution

Answer & Solution

Correct Answer

(A) \(C=\frac{2 k}{(k+1)} C\) 。

Step-by-step Solution

Detailed explanation

\(C_0 = \frac{\epsilon_0 A}{d}\) \(C = \frac{\epsilon_0 A}{(d-t) + \frac{t}{k}}\) \(C = \frac{\epsilon_0 A}{(d-\frac{d}{2}) + \frac{\frac{d}{2}}{k}}\) \(C = \frac{\epsilon_0 A}{\frac{d}{2} + \frac{d}{2k}}\)…
From CUET
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