CUET · PHYSICS · PYQ PAPER 2023
The capacitance of a capacitor is \( 4 \mu\text{F} \) and it's potential is 100 V. The energy released on discharging it fully will be
- A \( 0.02J\)
- B \( 0.04J\)
- C \( 0.025J\)
- D \( 0.05J\)
Answer & Solution
Correct Answer
(A) \( 0.02J\)
Step-by-step Solution
Detailed explanation
\( E = \frac{1}{2} C V^2 \) \( E = \frac{1}{2} (4 \times 10^{-6} \text{ F}) (100 \text{ V})^2 \) \( E = 0.02 \text{ J} \)
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