CUET · PHYSICS · PYQ PAPER 2025
The capacitance of a capacitor becomes \( \frac{9}{7} \) times of its original value when a dielectric slab of thickness \( t = \frac{d}{4} \) is inserted between the plates, where d is the separation between the plates. The dielectric constant of the slab is
- A 7
- B \(\frac{7}{15}\)
- C 9
- D \(\frac{15}{7}\)
Answer & Solution
Correct Answer
(C) 9
Step-by-step Solution
Detailed explanation
\( C = \frac{\epsilon_0 A}{d - t + \frac{t}{K}} \) \( \frac{9}{7} \frac{\epsilon_0 A}{d} = \frac{\epsilon_0 A}{d - \frac{d}{4} + \frac{\frac{d}{4}}{K}} \) \( \frac{9}{7d} = \frac{1}{d (1 - \frac{1}{4} + \frac{1}{4K})} \) \( \frac{9}{7} = \frac{1}{\frac{3}{4} + \frac{1}{4K}} \)…
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