CUET · PHYSICS · PYQ PAPER 2023
The capacitance of a capacitor becomes \(\frac{7}{6}\) times its original value if a dielectric slab of thickness \(t=\frac{2}{3} d\) is introduced between the plates, where \(d\) is the separation between the plates. The dielectric constant of the slab is:
- A \(\frac{11}{7}\)
- B \(\frac{7}{11}\)
- C \(\frac{11}{14}\)
- D \(\frac{14}{11}\)
Answer & Solution
Correct Answer
(D) \(\frac{14}{11}\)
Step-by-step Solution
Detailed explanation
\(C_0 = \frac{\epsilon_0 A}{d}\) \(C = \frac{\epsilon_0 A}{d - t + \frac{t}{k}}\) \(\frac{7}{6} \frac{\epsilon_0 A}{d} = \frac{\epsilon_0 A}{d - \frac{2}{3}d + \frac{\frac{2}{3}d}{k}}\) \(\frac{7}{6d} = \frac{1}{\frac{1}{3}d + \frac{2d}{3k}}\)…
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