CUET · PHYSICS · PYQ PAPER 2025
The atomic mass of \({ }_6^{12} C\) is 12.000000 u and that of \({ }_6^{18} C\) is 13.003354 u . The energy required to remove a neutron from \({ }_6^{13} C\) is
(Given: Mass of neutron is 1.008665 u and \(1 u =931 MeV\) )
- A 2 .73 MeV
- B 4.94 MeV
- C 6.08 MeV
- D 7.31 MeV
Answer & Solution
Correct Answer
(B) 4.94 MeV
Step-by-step Solution
Detailed explanation
\( \Delta m = (m({ }_6^{12} C) + m_n) - m({ }_6^{13} C) \) \( \Delta m = (12.000000 \text{ u} + 1.008665 \text{ u}) - 13.003354 \text{ u} = 0.005311 \text{ u} \) \( E = \Delta m \times 931 \text{ MeV/u} \)…
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