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CUET · PHYSICS · PYQ PAPER 2025

The angular momentum of an electron moving in the circular path of diameter D in a uniform magnetic field \( B_0 \) is:

  1. A zero
  2. B \( \frac{eB_0D}{2} \)
  3. C \( \frac{eB_0D^2}{2} \)
  4. D \( \frac{eB_0D^2}{4} \)
Verified Solution

Answer & Solution

Correct Answer

(D) \( \frac{eB_0D^2}{4} \)

Step-by-step Solution

Detailed explanation

\(evB_0 = \frac{mv^2}{R}\) \(mv = eB_0R\) \(L = mvr = (eB_0R)R = eB_0R^2\) \(L = eB_0 \left(\frac{D}{2}\right)^2 = \frac{eB_0D^2}{4}\)
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