CUET · PHYSICS · PYQ PAPER 2025
The angular momentum of an electron in the third orbit of a hydrogen atom is (Given \( h = 6.6 \times 10^{-34} \text{ J s} \))
- A \( 3.15 \times 10^{-34} \text{ J s} \)
- B \( 5.13 \times 10^{-34} \text{ J s} \)
- C \( 3.15 \times 10^{-36} \text{ J s} \)
- D \( 5.15 \times 10^{-36} \text{ J s} \)
Answer & Solution
Correct Answer
(A) \( 3.15 \times 10^{-34} \text{ J s} \)
Step-by-step Solution
Detailed explanation
\( L = n \frac{h}{2\pi} \) \( L = 3 \times \frac{6.6 \times 10^{-34}}{2 \times 3.14159} = 3.15 \times 10^{-34} \text{ J s} \)
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