CUET · PHYSICS · PYQ PAPER 2023
Ten capacitors each of \( 2 \mu \text{F} \) capacity were arranged in two rows such that first row contains 6 capacitors in series where as the rest were in second row. The equivalent capacitance of the network is :
- A \( \frac{5}{6} \mu \text{F} \)
- B \( 20 \mu \text{F} \)
- C \( \frac{24}{5} \mu \text{F} \)
- D \( \frac{4}{3} \mu \text{F} \)
Answer & Solution
Correct Answer
(A) \( \frac{5}{6} \mu \text{F} \)
Step-by-step Solution
Detailed explanation
\( C_{1} = \frac{2 \, \mu \text{F}}{6} = \frac{1}{3} \, \mu \text{F} \) \( C_{2} = \frac{2 \, \mu \text{F}}{4} = \frac{1}{2} \, \mu \text{F} \) \( C_{eq} = C_{1} + C_{2} = \frac{1}{3} + \frac{1}{2} = \frac{2+3}{6} = \frac{5}{6} \, \mu \text{F} \)
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