CUET · PHYSICS · PYQ PAPER 2023
Relation between rms voltage and peak voltage of an AC source is :
- A \( V_{rms} = \frac{2}{\pi} V_0 \)
- B \( V_{rms} = V_0 \sqrt{2} \)
- C \( V_{rms} = \frac{V_0}{\sqrt{2}} \)
- D \( V_{rms} = \frac{V_0}{2} \)
Answer & Solution
Correct Answer
(C) \( V_{rms} = \frac{V_0}{\sqrt{2}} \)
Step-by-step Solution
Detailed explanation
For a sinusoidal AC source, the root mean square (rms) voltage is the effective value that produces the same heating effect as a DC voltage. It is calculated by dividing the peak voltage ( \(V_0\) ) by \(\sqrt{2}\) (which is approximately \(0.707 \times V_0\) ). C)…
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