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CUET · PHYSICS · PYQ PAPER 2024

Radiation of frequency \(2 v_0\) incident on a metal with threshold frequency \(v_0\) results in maximum kinetic energy of photoelectrons as :

  1. A No photoelectrons emitted
  2. B All have kinetic energy equal to h\(v_0\)
  3. C Maximum kinetic energy can be h\(v_0\)
  4. D Maximum kinetic energy will be 2h\(v_0\)
Verified Solution

Answer & Solution

Correct Answer

(C) Maximum kinetic energy can be h\(v_0\)

Step-by-step Solution

Detailed explanation

\(KE_{max} = hf - hf_0\) C) Maximum kinetic energy can be\(KE_{max} = h(2v_0) - h(v_0) = hv_0\)