CUET · PHYSICS · PYQ PAPER 2023
Masses of three wires of copper are in the ratio of \(1: 3: 5\) and their lengths are in the ratio of 5:31. The ratio of their electrical resistance are:
- A \(1: 3: 5\)
- B \(5: 3: 1\)
- C \(1: 15: 125\)
- D \(125: 15: 1\)
Answer & Solution
Correct Answer
(D) \(125: 15: 1\)
Step-by-step Solution
Detailed explanation
\(R \propto \frac{L^2}{m}\) \(R_1:R_2:R_3 = \frac{L_1^2}{m_1}:\frac{L_2^2}{m_2}:\frac{L_3^2}{m_3}\) \(R_1:R_2:R_3 = \frac{5^2}{1}:\frac{3^2}{3}:\frac{1^2}{5}\) \(R_1:R_2:R_3 = 25:\frac{9}{3}:\frac{1}{5}\) \(R_1:R_2:R_3 = 25:3:\frac{1}{5}\) \(R_1:R_2:R_3 = 125:15:1\)
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