CUET · PHYSICS · PYQ PAPER 2024
Magnetic moment of a thin bar magnet is 'M'. If it is bent into a semicircular form, its new magnetic moment will be :
- A M/\(\pi\)
- B M/2
- C M
- D 2M/\(\pi\)
Answer & Solution
Correct Answer
(D) 2M/\(\pi\)
Step-by-step Solution
Detailed explanation
\( M = m L \) \( L = \pi r \implies 2r = \frac{2L}{\pi} \) \( M' = m (2r) = m \left( \frac{2L}{\pi} \right) \) \( M' = (mL) \frac{2}{\pi} = M \frac{2}{\pi} \) \( M' = \frac{2M}{\pi} \)
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