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CUET · PHYSICS · PYQ PAPER 2025

Light of frequency \( 8.27 \times 10^{14} \text{ Hz} \) is incident on a metal surface. Electrons with maximum speed \( 6.6 \times 10^5 \text{ m/s} \) are ejected. The threshold frequency for photoemission of electrons will be (given \( h = 6.6 \times 10^{-34} \text{ Js} \), and mass of electron = \( m_e = 9 \times 10^{-31} \text{ kg} \)) :

  1. A \( 5.30 \times 10^{14} \text{ Hz} \)
  2. B \( 4.74 \times 10^{14} \text{ Hz} \)
  3. C \( 3.84 \times 10^{14} \text{ Hz} \)
  4. D \( 5.94 \times 10^{14} \text{ Hz} \)
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Answer & Solution

Correct Answer

(A) \( 5.30 \times 10^{14} \text{ Hz} \)

Step-by-step Solution

Detailed explanation

\( hf = hf_0 + \frac{1}{2} m_e v_{max}^2 \) \( f_0 = f - \frac{m_e v_{max}^2}{2h} \) \( f_0 = 8.27 \times 10^{14} - \frac{9 \times 10^{-31} \times (6.6 \times 10^5)^2}{2 \times 6.6 \times 10^{-34}} \)…
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