CUET · PHYSICS · PYQ PAPER 2025
Ionization potential of a hydrogen atom is 13.6 V. Hydrogen atom in the ground state is excited by monochromatic radiation of photon energy 12.75 eV. The number of spectral lines emitted by hydrogen atom will be
- A 3
- B 4
- C 6
- D 5
Answer & Solution
Correct Answer
(C) 6
Step-by-step Solution
Detailed explanation
\(E_n = E_1 + \Delta E\) \(E_n = -13.6 \text{ eV} + 12.75 \text{ eV} = -0.85 \text{ eV}\) \(n^2 = \frac{-13.6 \text{ eV}}{E_n} = \frac{-13.6}{-0.85} = 16\) \(n = 4\) \(\text{Number of spectral lines} = \frac{n(n-1)}{2}\)…
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