CUET · PHYSICS · PYQ PAPER 2025
Interference fringes may be observed due to the superposition of two light waves represented by :
- A \( y_1 = a \sin(\omega t), \text{ } y_2 = a \sin(2\omega t) \)
- B \( y_1 = a \sin(\omega t), \text{ } y_2 = 2a \sin(2\omega t + \delta) \)
- C \( y_1 = 2a \sin(2\omega t), \text{ } y_2 = 2a \sin(2\omega t + \delta) \)
- D \( y_1 = 2a \sin(\omega t), \text{ } y_2 = 2a \sin(2\omega t + \delta) \)
Answer & Solution
Correct Answer
(C) \( y_1 = 2a \sin(2\omega t), \text{ } y_2 = 2a \sin(2\omega t + \delta) \)
Step-by-step Solution
Detailed explanation
\( y_1 = 2a \sin(2\omega t), \text{ } y_2 = 2a \sin(2\omega t + \delta) \) The frequencies are the same, and there is a phase difference, which is a condition for interference fringes.
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