CUET · PHYSICS · PYQ PAPER 2023
In Young's double slit experiment using monochromatic light of wavelength \(\lambda\), the intensity of light at a point on the screen where path difference is \(\lambda\), is 'T' units. What is the intensity of light at a point where path difference is \(\frac{\lambda}{4}\) ?
- A Zero
- B 3T
- C \(\frac{T}{3}\)
- D \(\frac{T}{2}\)
Answer & Solution
Correct Answer
(D) \(\frac{T}{2}\)
Step-by-step Solution
Detailed explanation
\(\phi_1 = \frac{2\pi}{\lambda} \delta_1 = \frac{2\pi}{\lambda} (\lambda) = 2\pi\) \(T = I_0 \cos^2\left(\frac{\phi_1}{2}\right) = I_0 \cos^2(\pi) = I_0\) \(\phi_2 = \frac{2\pi}{\lambda} \delta_2 = \frac{2\pi}{\lambda} \left(\frac{\lambda}{4}\right) = \frac{\pi}{2}\)…
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