CUET · PHYSICS · PYQ PAPER 2023
In Young's double slit experiment, the light has a frequency \( 12 \times 10^{14} \text{ Hz} \) and the distance between the centres of adjacent fringes is 0.8 mm. If the screen is 1.6 m away, what is the distance between the slits? (Take speed of light \( c = 3 \times 10^8 \text{ m s}^{-1} \))
- A \( 5.00 \times 10^{-4} \text{ m} \)
- B \( 5.92 \times 10^{-4} \text{ m} \)
- C \( 2.00 \times 10^{-4} \text{ m} \)
- D \( 1.25 \times 10^{-4} \text{ m} \)
Answer & Solution
Correct Answer
(A) \( 5.00 \times 10^{-4} \text{ m} \)
Step-by-step Solution
Detailed explanation
\(\lambda = \frac{c}{f} = \frac{3 \times 10^8 \text{ m s}^{-1}}{12 \times 10^{14} \text{ Hz}} = 2.5 \times 10^{-7} \text{ m}\)…
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