CUET · PHYSICS · PYQ PAPER 2023
In Young's double slit experiment the intensity at a point where path difference is \( \lambda/6 \) is I. If \( I_0 \) denotes the maximum intensity, then \( I/I_0 \) is equal to :
- A \( \frac{1}{\sqrt{2}} \)
- B \( \frac{\sqrt{3}}{2} \)
- C \( \frac{3}{4} \)
- D \( \frac{1}{2} \)
Answer & Solution
Correct Answer
(C) \( \frac{3}{4} \)
Step-by-step Solution
Detailed explanation
\( \phi = \frac{2\pi}{\lambda} \Delta x = \frac{2\pi}{\lambda} (\frac{\lambda}{6}) = \frac{\pi}{3} \) \( \frac{I}{I_0} = \cos^2(\frac{\phi}{2}) = \cos^2(\frac{\pi/3}{2}) = \cos^2(\frac{\pi}{6}) \) \( \frac{I}{I_0} = (\frac{\sqrt{3}}{2})^2 = \frac{3}{4} \)
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