CUET · PHYSICS · PYQ PAPER 2025
In the nuclear decay given below, the particles emitted in the sequence are:

- A \( \alpha, \beta, \gamma \)
- B \( \gamma, \beta, \alpha \)
- C \( \beta, \gamma, \alpha \)
- D \( \beta, \alpha, \gamma \)
Answer & Solution
Correct Answer
(D) \( \beta, \alpha, \gamma \)
Step-by-step Solution
Detailed explanation
\( _{92}^{238}U \rightarrow _{90}^{234}Th \): \(\Delta A = 4, \Delta Z = 2 \implies \alpha \) \( _{90}^{234}Th \rightarrow _{91}^{234}Pa \): \(\Delta A = 0, \Delta Z = -1 \implies \beta \) \( _{91}^{234}Pa \rightarrow _{91}^{234}Pa \):…
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