CUET · PHYSICS · PYQ PAPER 2025
In the hydrogen atom, an electron revolves around the nucleus in a circular orbit of radius \( 5.11 \times 10^{-11} \text{ m} \) with a frequency of \( 6.8 \times 10^{15} \text{ Hz} \). The magnetic field at the centre of the orbit is :
- A 6.7 T
- B 13.4 T
- C 20.1 T
- D 26.8 T
Answer & Solution
Correct Answer
(B) 13.4 T
Step-by-step Solution
Detailed explanation
\( B = \frac{\mu_0 I}{2R} = \frac{\mu_0 e f}{2R} \) \( B = \frac{(4\pi \times 10^{-7} \text{ T m/A}) (1.602 \times 10^{-19} \text{ C}) (6.8 \times 10^{15} \text{ Hz})}{2 (5.11 \times 10^{-11} \text{ m})} \) \( B \approx 13.4 \text{ T} \)
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