CUET · PHYSICS · PYQ PAPER 2025
In the given figure a rod PQ of length 2.5 m can slide without friction. The value of R is 5.0 \( \Omega \) and a magnetic field of 2 T is directed perpendicularly into the paper. The force F required to move the rod to the right at a constant speed of 1.0 m/s will be
- A 2.5 N
- B 5.0 N
- C 10 N
- D 1 N
Answer & Solution
Correct Answer
(B) 5.0 N
Step-by-step Solution
Detailed explanation
\( \mathcal{E} = Blv \) \( \mathcal{E} = (2 \text{ T})(2.5 \text{ m})(1.0 \text{ m/s}) = 5.0 \text{ V} \) \( I = \frac{\mathcal{E}}{R} \) \( I = \frac{5.0 \text{ V}}{5.0 \, \Omega} = 1.0 \text{ A} \) \( F = BIL \)…
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