CUET · PHYSICS · PYQ PAPER 2025
In the given circuit, \( R_1 = 6 \Omega \), \( R_2 = 3 \Omega \), \( C_1 = 4 \mu F \) and \( C_2 = 5 \mu F \). When key K is closed, the charge stored in \( C_1 \) is
- A \( 24 \mu C \)
- B \( 20 \mu C \)
- C \( 12 \mu C \)
- D \( 16 \mu C \)
Answer & Solution
Correct Answer
(A) \( 24 \mu C \)
Step-by-step Solution
Detailed explanation
\(R_{\text {total }}=R_1+R_2=6 \Omega+3 \Omega=9 \Omega\). \(I=\frac{V}{R_{\text {total }}}=\frac{9 V}{9 \Omega}=1 A\). \(V_{R 2}=I \times R_2=1 A \times 3 \Omega=3 V\). The potential difference across \(C_1\) is \(\Delta V=9 V-3 V=6 V\). \(Q=C \times V\)…
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