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CUET · PHYSICS · PYQ PAPER 2025

In the circuit shown below, \(C_1 = 6 \mu F\), \(C_2 = 3 \mu F\) and battery \(B = 40 V\). Initially, switch \(A_1\) is opened and the switch \(A_2\) is closed. Now switch \(A_2\) is opened and \(A_1\) is closed. The charge on \(C_2\) will be
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  1. A \(100 \mu C\)
  2. B \(40 \mu C\)
  3. C \(80 \mu C\)
  4. D \(18 \mu C\)
Verified Solution

Answer & Solution

Correct Answer

(C) \(80 \mu C\)

Step-by-step Solution

Detailed explanation

\(V_c=\frac{Q_{\text {total }}}{C_{\text {equivalent }}}=\frac{Q_1}{C_1+C_2}\) \(V_c=\frac{240 \mu C }{6 \mu F+3 \mu F}=\frac{240}{9} V=\frac{80}{3} V\) \(Q_2^{\prime}=C_2 \times V_c\) \(Q_2^{\prime}=3 \mu F \times\left(\frac{80}{3} V\right)\) \(Q_2^{\prime}=80 \mu C\)
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