CUET · PHYSICS · PYQ PAPER 2025
In an AC generator, a 100 turns coil of area \(0.10 \text{ m}^2\) rotates at 50 Hz in a uniform magnetic field of 0.01 T. The maximum voltage generated in the coil is
- A 27 V
- B 314 V
- C 31.4 V
- D 10 V
Answer & Solution
Correct Answer
(C) 31.4 V
Step-by-step Solution
Detailed explanation
\( \omega = 2\pi f = 2\pi(50 \text{ Hz}) = 100\pi \text{ rad/s} \) \( \mathcal{E}_{max} = NAB\omega = (100)(0.10 \text{ m}^2)(0.01 \text{ T})(100\pi \text{ rad/s}) = 31.4 \text{ V} \)
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