CUET · PHYSICS · PYQ PAPER 2025
In an a. c. series LCR circuit, the applied voltage is \(v=(100 \sqrt{2}) \sin (\omega t+\pi / 4)\) volt. Given that \(R=30 \Omega, X_L=50 \Omega\) and \(X_C=10 \Omega\). The value of power dissipated in the circuit is
- A 200 W
- B Zero
- C 100 W
- D 120 W
Answer & Solution
Correct Answer
(D) 120 W
Step-by-step Solution
Detailed explanation
\(V_{rms} = \frac{100 \sqrt{2}}{\sqrt{2}} = 100 \text{ V}\) \(X = X_L - X_C = 50 - 10 = 40 \Omega\) \(Z = \sqrt{R^2 + X^2} = \sqrt{30^2 + 40^2} = \sqrt{900 + 1600} = \sqrt{2500} = 50 \Omega\) \(I_{rms} = \frac{V_{rms}}{Z} = \frac{100}{50} = 2 \text{ A}\)…
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