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CUET · PHYSICS · PYQ PAPER 2025

In a Young's double slit experiment, two slits are separated by 3 mm and the screen is placed 1.5 m away. The distance between two consecutive minima for a light of wavelength 420 nm is

  1. A 0.84 mm
  2. B 0.63 mm
  3. C 0.42 mm
  4. D 0.21 mm
Verified Solution

Answer & Solution

Correct Answer

(D) 0.21 mm

Step-by-step Solution

Detailed explanation

\( \beta = \frac{\lambda L}{d} \) \( \beta = \frac{(420 \times 10^{-9} \, \text{m})(1.5 \, \text{m})}{3 \times 10^{-3} \, \text{m}} \) \( \beta = 210 \times 10^{-6} \, \text{m} = 0.21 \, \text{mm} \)