CUET · PHYSICS · PYQ PAPER 2025
In a Young's double slit experiment, two slits are separated by 3 mm and the screen is placed 1.5 m away. The distance between two consecutive minima for a light of wavelength 420 nm is
- A 0.84 mm
- B 0.63 mm
- C 0.42 mm
- D 0.21 mm
Answer & Solution
Correct Answer
(D) 0.21 mm
Step-by-step Solution
Detailed explanation
\( \beta = \frac{\lambda L}{d} \) \( \beta = \frac{(420 \times 10^{-9} \, \text{m})(1.5 \, \text{m})}{3 \times 10^{-3} \, \text{m}} \) \( \beta = 210 \times 10^{-6} \, \text{m} = 0.21 \, \text{mm} \)
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