CUET · PHYSICS · PYQ PAPER 2025
In a Young's double-slit experiment, two slits are 1.5 mm apart while the screen is 1.2 m away. When a light of wavelength 600 nm is incident on slits, the fringe width will be
- A 0.48 mm
- B 4.5 mm
- C 4.8 mm
- D 4.2 mm
Answer & Solution
Correct Answer
(A) 0.48 mm
Step-by-step Solution
Detailed explanation
\(\beta = \frac{\lambda D}{d}\) \(\beta = \frac{(600 \times 10^{-9} \text{ m}) \times (1.2 \text{ m})}{1.5 \times 10^{-3} \text{ m}} = 0.00048 \text{ m}\) \(\beta = 0.48 \text{ mm}\)
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