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CUET · PHYSICS · PYQ PAPER 2025

In a Young's double-slit experiment, two slits are 1.5 mm apart while the screen is 1.2 m away. When a light of wavelength 600 nm is incident on slits, the fringe width will be

  1. A 0.48 mm
  2. B 4.5 mm
  3. C 4.8 mm
  4. D 4.2 mm
Verified Solution

Answer & Solution

Correct Answer

(A) 0.48 mm

Step-by-step Solution

Detailed explanation

\(\beta = \frac{\lambda D}{d}\) \(\beta = \frac{(600 \times 10^{-9} \text{ m}) \times (1.2 \text{ m})}{1.5 \times 10^{-3} \text{ m}} = 0.00048 \text{ m}\) \(\beta = 0.48 \text{ mm}\)