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CUET · PHYSICS · PYQ PAPER 2025

In a Young's double slit experiment, the distance between slits is 2.5 mm and the screen is placed 2 m away from the slits. The fringe width for a light of wavelength 400 nm is

  1. A 2.5 mm
  2. B 3.32 mm
  3. C 0.16 mm
  4. D 0.32 mm
Verified Solution

Answer & Solution

Correct Answer

(D) 0.32 mm

Step-by-step Solution

Detailed explanation

\(\beta = \frac{\lambda D}{d}\) \(\beta = \frac{(400 \times 10^{-9} \text{ m}) \times (2 \text{ m})}{2.5 \times 10^{-3} \text{ m}}\) \(\beta = 0.32 \times 10^{-3} \text{ m} = 0.32 \text{ mm}\)