CUET · PHYSICS · PYQ PAPER 2025
In a Young's double slit experiment, interference fringes were produced on a screen placed 1.8 m from the two slits 0.3 mm apart and illuminated by light of wavelength 600 nm. The fringe width is
- A 0.9 mm
- B 1.0 mm
- C 3.6 mm
- D 7.2 mm
Answer & Solution
Correct Answer
(C) 3.6 mm
Step-by-step Solution
Detailed explanation
Fringe width \( \beta = \frac{\lambda D}{d} \) \( \beta = \frac{(600 \times 10^{-9} \text{ m}) \times (1.8 \text{ m})}{0.3 \times 10^{-3} \text{ m}} \) \( \beta = 3.6 \times 10^{-3} \text{ m} = 3.6 \text{ mm} \)
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