CUET · PHYSICS · PYQ PAPER 2025
In a Young's double slit experiment, a light of wavelength 550 nm is used to get fringes on screen 1.2 m away from the slits. The distance between the two slits is 1.5 mm. The fringe width is
- A 4.4 mm
- B 0.44 mm
- C 5.5 mm
- D 4.0 mm
Answer & Solution
Correct Answer
(B) 0.44 mm
Step-by-step Solution
Detailed explanation
\(\beta = \frac{\lambda D}{d}\) \(\beta = \frac{(550 \times 10^{-9} \text{ m})(1.2 \text{ m})}{1.5 \times 10^{-3} \text{ m}}\) \(\beta = 4.4 \times 10^{-4} \text{ m} = 0.44 \text{ mm}\)
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