CUET · PHYSICS · PYQ PAPER 2025
In a single slit diffraction experiment, the aperture of the slit is 3 mm. A monochromatic light of wavelength 620 nm is normally incident on the slit. If the distance between the slit and the screen is 1.2 m, then the separation between the first order minima and the third order maxima on one side of the screen is
- A \( 1.620 \times 10^{-4} \text{ m} \)
- B \(2. 770 \times 10^{-4} \text{ m} \)
- C \( 6.20 \times 10^{-4} \text{ m} \)
- D \( 7.70 \times 10^{-4} \text{ m} \)
Answer & Solution
Correct Answer
(C) \( 6.20 \times 10^{-4} \text{ m} \)
Step-by-step Solution
Detailed explanation
Position of \(m\)-th minima: \( y_m = \frac{m \lambda D}{a} \) Position of \(m'\)-th maxima: \( y_{m'} = \frac{(m' + 0.5) \lambda D}{a} \) Separation \( \Delta y = y_3 - y_1 = \frac{(3.5 - 1) \lambda D}{a} = \frac{2.5 \lambda D}{a} \)…
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