CUET · PHYSICS · PYQ PAPER 2025
In a single slit diffraction experiment, first minima for \( \lambda_1 = 600 \, \text{nm} \) coincides with first maxima for wavelength \( \lambda_2 \). The value of \( \lambda_2 \) is
- A 400 nm
- B 600 nm
- C 440 nm
- D 300 nm
Answer & Solution
Correct Answer
(A) 400 nm
Step-by-step Solution
Detailed explanation
\(\lambda_1 = \frac{3}{2}\lambda_2\) \(\lambda_2 = \frac{2}{3}\lambda_1\) \(\lambda_2 = \frac{2}{3}(600 \text{ nm})\) \(\lambda_2 = 400 \text{ nm}\)
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