CUET · PHYSICS · PYQ PAPER 2025
In a series LCR circuit, \( R = 1 \text{ k}\Omega, C = 2 \text{ } \mu\text{F} \) and the voltage across R is 100 V at resonant frequency \( \omega = 200 \text{ rad/s} \). At resonant frequency, the voltage across L is:
- A 40 V
- B 250 V
- C 2500 V
- D 100 V
Answer & Solution
Correct Answer
(B) 250 V
Step-by-step Solution
Detailed explanation
\( I = \frac{V_R}{R} = \frac{100 \text{ V}}{1000 \text{ } \Omega} = 0.1 \text{ A} \) \( X_L = \frac{1}{\omega C} = \frac{1}{(200 \text{ rad/s})(2 \times 10^{-6} \text{ F})} = 2500 \text{ } \Omega \) \( V_L = I \cdot X_L = (0.1 \text{ A})(2500 \text{ } \Omega) = 250 \text{ V} \)
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