CUET · PHYSICS · PYQ PAPER 2025
In a series LCR circuit, \( C = 80 \, \mu\text{F} \), \( L = 5.0 \, \text{H} \) and \( R = 40 \, \Omega \) are connected to a variable frequency source of 240 V. The angular frequency of the source which drives the circuit at resonance will be:
- A \( 5 \, \text{rad s}^{-1} \)
- B \( 25 \, \text{rad s}^{-1} \)
- C \( 0.05 \, \text{rad s}^{-1} \)
- D \( 50 \, \text{rad s}^{-1} \)
Answer & Solution
Correct Answer
(D) \( 50 \, \text{rad s}^{-1} \)
Step-by-step Solution
Detailed explanation
\( \omega_0 = \frac{1}{\sqrt{LC}} \) \( \omega_0 = \frac{1}{\sqrt{5.0 \, \text{H} \times 80 \times 10^{-6} \, \text{F}}} \) \( \omega_0 = \frac{1}{\sqrt{400 \times 10^{-6}}} = \frac{1}{\sqrt{4 \times 10^{-4}}} = \frac{1}{2 \times 10^{-2}} \)…
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