CUET · PHYSICS · PYQ PAPER 2025
In a series LCR circuit, \( C = 5 \text{ }\mu\text{F} \) and \( \omega = 1000 \text{ rad/s} \). The value of inductance L for which the current is maximum in this circuit will be :
- A 100 mH
- B 10 mH
- C 50 mH
- D 200 mH
Answer & Solution
Correct Answer
(D) 200 mH
Step-by-step Solution
Detailed explanation
For maximum current (resonance): \(X_L = X_C\) \( \omega L = \frac{1}{\omega C} \) \( L = \frac{1}{\omega^2 C} = \frac{1}{(1000)^2 \times (5 \times 10^{-6})} \) \( L = \frac{1}{10^6 \times 5 \times 10^{-6}} = \frac{1}{5} = 0.2 \text{ H} \) \( L = 200 \text{ mH} \)
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