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CUET · PHYSICS · PYQ PAPER 2023

In a potentiometer arrangement for comparing emf of two cells, it was found that a cell of emf 1.25 V gives a balance point at 0.35 m length of the wire. On replacing the cell by another cell, the balance point shifted to 0.63 m. The emf of the second cell is :

  1. A 1.5 V
  2. B 0.69 V
  3. C 1.75 V
  4. D 2.25 V
Verified Solution

Answer & Solution

Correct Answer

(D) 2.25 V

Step-by-step Solution

Detailed explanation

\(E_2 = E_1 \frac{L_2}{L_1}\) \(E_2 = 1.25\, \text{V} \times \frac{0.63\, \text{m}}{0.35\, \text{m}}\) \(E_2 = 2.25\, \text{V}\)
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