CUET · PHYSICS · PYQ PAPER 2025
In a parallel plate capacitor, each plate has an area of \(7 \times 10^{-3} \text{ m}^2\) and the distance between the plates is 2 mm. The space between the plates of the capacitor is filled with mica having dielectric constant 6. If the capacitor is connected to 120 V supply, the charge on each plate of the capacitor will be (Given: permittivity of the vacuum \(\epsilon_0 = 8.85 \times 10^{-12}\) SI unit)
- A \(2.23 \times 10^{-10} \text{ C}\)
- B \(2.23 \times 10^{-8} \text{ C}\)
- C \(3.71 \times 10^{-9} \text{ C}\)
- D \(3.71 \times 10^{-8} \text{ C}\)
Answer & Solution
Correct Answer
(B) \(2.23 \times 10^{-8} \text{ C}\)
Step-by-step Solution
Detailed explanation
\(C = \frac{K \epsilon_0 A}{d} = \frac{6 \times 8.85 \times 10^{-12} \times 7 \times 10^{-3}}{2 \times 10^{-3}} = 1.8585 \times 10^{-10} \text{ F}\) \(Q = CV = 1.8585 \times 10^{-10} \times 120 = 2.2302 \times 10^{-8} \text{ C}\)
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