CUET · PHYSICS · PYQ PAPER 2025
In a nuclear fission reaction given below, the three neutrons are released. The value of x and y are\( {}_{0}^{1}n + {}_{92}^{235}U \rightarrow {}_{56}^{x}Ba + {}_{y}^{89}Kr + 3{}_{0}^{1}n \)
- A x = 147, y = 36
- B x = 144, y = 36
- C x = 147, y = 33
- D x = 144, y = 33
Answer & Solution
Correct Answer
(B) x = 144, y = 36
Step-by-step Solution
Detailed explanation
Conservation of mass number: \(1 + 235 = x + 89 + 3 \times 1 \) \(236 = x + 92 \) \(x = 144 \) Conservation of atomic number: \(0 + 92 = 56 + y + 3 \times 0 \) \(92 = 56 + y \) \(y = 36 \)
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