CUET · PHYSICS · PYQ PAPER 2025
In a large building, there are 20 bulbs of 40 W each, 5 bulbs of 100 W each, 5 fans of 80 W each, and 1 heater of 1 kW. The voltage supply is 220 V. The minimum capacity of the main fuse of the building should be
- A 12.27 A
- B 10.42 A
- C 8.31 A
- D 6 A
Answer & Solution
Correct Answer
(A) 12.27 A
Step-by-step Solution
Detailed explanation
\(P_{total} = (20 \times 40) + (5 \times 100) + (5 \times 80) + (1 \times 1000) \) \(P_{total} = 800 + 500 + 400 + 1000 = 2700 \, \text{W}\) \(I = \frac{P_{total}}{V} = \frac{2700 \, \text{W}}{220 \, \text{V}}\) \(I \approx 12.27 \, \text{A}\) Minimum fuse capacity = 12.27 A
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