CUET · PHYSICS · PYQ PAPER 2025
In a diffraction experiment, the screen is placed \( D = 2 \text{ m} \) away from a narrow slit. The first minimum observed is at \( x = 5 \text{ mm} \) on either side of the central maximum for wavelength of \( \lambda = 5 \times 10^{-5} \text{ cm} \). The width of the slit a is:
- A 0.01 cm
- B 0.02 cm
- C 0.11 cm
- D 0.12 cm
Answer & Solution
Correct Answer
(B) 0.02 cm
Step-by-step Solution
Detailed explanation
\( a = \frac{\lambda D}{x} \) \( a = \frac{(5 \times 10^{-5} \text{ cm}) (200 \text{ cm})}{0.5 \text{ cm}} \) \( a = 0.02 \text{ cm} \)
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