CUET · PHYSICS · PYQ PAPER 2025
If the mass of a proton is \( m_p = 1.007825 \text{ u} \) and the mass of the neutron is \( m_n = 1.008665 \text{ u} \), the mass defect in the formation of \( {}_{3}^{7}\text{Li} \) nucleus is: (take the mass of Lithium nucleus as \( M_{Li} = 7.000000 \text{ u} \))
- A 0.058135 u
- B 0.057295 u
- C 0.016490 u
- D 0.056420 u
Answer & Solution
Correct Answer
(A) 0.058135 u
Step-by-step Solution
Detailed explanation
\( Z = 3, N = 7 - 3 = 4 \) \( \Delta m = (Z \cdot m_p + N \cdot m_n) - M_{Li} \) \( \Delta m = (3 \cdot 1.007825 \text{ u} + 4 \cdot 1.008665 \text{ u}) - 7.000000 \text{ u} \) \( \Delta m = (3.023475 \text{ u} + 4.034660 \text{ u}) - 7.000000 \text{ u} \)…
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