CUET · PHYSICS · PYQ PAPER 2023
If 'n' identical resistors, each of value 'R' are first connected in series to a battery of emf 'E' and internal resistance 'R', the current drawn is 'I'. Now if they are connected in parallel, then the current drawn is '5 I'. The value of n is
- A 5
- B 6
- C 10
- D 25
Answer & Solution
Correct Answer
(A) 5
Step-by-step Solution
Detailed explanation
\(I = \frac{E}{nR + R} = \frac{E}{R(n+1)}\) \(I' = \frac{E}{\frac{R}{n} + R} = \frac{E}{R(\frac{1}{n}+1)} = \frac{nE}{R(n+1)}\) \(I' = 5I \Rightarrow \frac{nE}{R(n+1)} = 5 \left( \frac{E}{R(n+1)} \right)\) \(n = 5\)
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