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CUET · PHYSICS · PYQ PAPER 2025

If 'n' identical resistors, each of value 'R' are first connected in series to a battery of emf 'E' and internal resistance 'R', the current drawn is 'I'. Now if they are connected in parallel, then the current drawn is '5 I'. The value of n is

  1. A 5
  2. B 6
  3. C 10
  4. D 25
Verified Solution

Answer & Solution

Correct Answer

(A) 5

Step-by-step Solution

Detailed explanation

\( I = \frac{E}{nR + R} = \frac{E}{R(n+1)} \) \( 5I = \frac{E}{\frac{R}{n} + R} = \frac{nE}{R(n+1)} \) \( 5 \left( \frac{E}{R(n+1)} \right) = \frac{nE}{R(n+1)} \) \( n = 5 \)