CUET · PHYSICS · PYQ PAPER 2023
If \(I=I_0 \sin \left(\omega t-\frac{\pi}{2}\right)\) and \(E=E_0 \sin \omega t\), then the AC power consumed is
- A \(P=\frac{E_0 I_0}{\sqrt{2}}\)
- B \(P=\sqrt{2} E_0 I_0\)
- C \(P=\frac{E_0 I_0}{2}\)
- D \(P=0\)
Answer & Solution
Correct Answer
(D) \(P=0\)
Step-by-step Solution
Detailed explanation
\(\phi = \omega t - (\omega t - \frac{\pi}{2}) = \frac{\pi}{2}\) \(P = \frac{E_0 I_0}{2} \cos \phi\) \(P = \frac{E_0 I_0}{2} \cos \left(\frac{\pi}{2}\right)\) \(P = \frac{E_0 I_0}{2} \cdot 0 = 0\)
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