CUET · PHYSICS · PYQ PAPER 2023
If charge is moving perpendicular to uniform magnetic field then its time period of revolution is:
- A independent of its radius of circular path
- B independent of magnitude of magnetic field
- C independent of magnitude of charge
- D independent of mass of charged particle
Answer & Solution
Correct Answer
(A) independent of its radius of circular path
Step-by-step Solution
Detailed explanation
\( qvB = \frac{mv^2}{r} \) \( v = \frac{2\pi r}{T} \) \( q \left(\frac{2\pi r}{T}\right) B = \frac{m}{r} \left(\frac{2\pi r}{T}\right)^2 \) \( \frac{q2\pi r B}{T} = \frac{m 4\pi^2 r}{T^2} \) \( T = \frac{2\pi m}{qB} \) independent of its radius of circular path
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